Leetcode 860 Solution

This article provides solution to leetcode question 860 (design-circular-queue)

https://leetcode.com/problems/design-circular-queue

Solution

class MyCircularQueue:
def __init__(self, k: int): """ Initialize your data structure here. Set the size of the queue to be k. """ self.a = [0] * k self.k = k
self.head = 0 self.length = 0
def enQueue(self, value: int) -> bool: """ Insert an element into the circular queue. Return true if the operation is successful. """ if self.length == self.k: return False
self.a[(self.head + self.length) % self.k] = value self.length += 1
return True
def deQueue(self) -> bool: """ Delete an element from the circular queue. Return true if the operation is successful. """ if self.length == 0: return False
self.head = (self.head + 1) % self.k self.length -= 1
return True
def Front(self) -> int: """ Get the front item from the queue. """ if self.length == 0: return -1 return self.a[self.head]
def Rear(self) -> int: """ Get the last item from the queue. """ if self.length == 0: return -1 return self.a[(self.head + self.length - 1) % self.k]
def isEmpty(self) -> bool: """ Checks whether the circular queue is empty or not. """ return self.length == 0
def isFull(self) -> bool: """ Checks whether the circular queue is full or not. """ return self.length == self.k
# Your MyCircularQueue object will be instantiated and called as such: # obj = MyCircularQueue(k) # param_1 = obj.enQueue(value) # param_2 = obj.deQueue() # param_3 = obj.Front() # param_4 = obj.Rear() # param_5 = obj.isEmpty() # param_6 = obj.isFull()