Leetcode 690 Solution

This article provides solution to leetcode question 690 (employee-importance)
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https://leetcode.com/problems/employee-importance

Solution

"""
# Employee info
class Employee:
    def __init__(self, id, importance, subordinates):
        # It's the unique id of each node.
        # unique id of this employee
        self.id = id
        # the importance value of this employee
        self.importance = importance
        # the id of direct subordinates
        self.subordinates = subordinates
"""
class Solution:
    def getImportance(self, employees, id):
        """
        :type employees: Employee
        :type id: int
        :rtype: int
        """
        employees = {
            employee.id: employee
            for employee in employees
        }



        def dfs(employee):
            return employee.importance + sum([dfs(employees[report]) for report in employee.subordinates])



        return dfs(employees[id])