Leetcode 288 Solution

This article provides solution to leetcode question 288 (unique-word-abbreviation)
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https://leetcode.com/problems/unique-word-abbreviation

Solution

class ValidWordAbbr {
    string getAbbr(const string& word)
    {
        if (word.size() <= 2)
            return word;

        string abbr = word.substr(0, 1);
        abbr += to_string(word.size() - 2);
        abbr += word[word.size() - 1];
        return abbr;
    }

    unordered_map<string, int> s;
    unordered_map<string, int> words;

public:
    ValidWordAbbr(vector<string> dictionary) {
        for (auto word : dictionary)
        {
            if (words[word] > 0)
                continue;

            words[word]++;
            auto abbr = getAbbr(word);
            s[abbr]++;
        }
    }

    bool isUnique(string word) {
        auto abbr = getAbbr(word);
        return words[word] == 0 && s[abbr] == 0 || words[word] == 1 && s[abbr] == 1;
    }
};

/**
 * Your ValidWordAbbr object will be instantiated and called as such:
 * ValidWordAbbr obj = new ValidWordAbbr(dictionary);
 * bool param_1 = obj.isUnique(word);
 */