Leetcode 1409 Solution

This article provides solution to leetcode question 1409 (minimum-number-of-flips-to-convert-binary-matrix-to-zero-matrix)

https://leetcode.com/problems/minimum-number-of-flips-to-convert-binary-matrix-to-zero-matrix

Solution

class Solution: def minFlips(self, mat: List[List[int]]) -> int: m = len(mat) n = len(mat[0])
def flip(mat, i, j): nonlocal m nonlocal n
new_mat = copy.deepcopy(mat)
new_mat[i][j] = 1 - new_mat[i][j] for ni, nj in [ (i, j + 1), (i + 1, j), (i - 1, j), (i, j - 1), ]: if not (0 <= ni < m and 0 <= nj < n): continue
new_mat[ni][nj] = 1 - new_mat[ni][nj] return new_mat
def get_key(mat): return ":".join([",".join([str(v) for v in row]) for row in mat])
def is_all_zero(mat): for row in mat: for v in row: if v != 0: return False return True
q = collections.deque() visited = set()
q.append(mat) visited.add(get_key(mat))
step = 0 while q: s = len(q) for _ in range(s): mat = q.popleft()
if is_all_zero(mat): return step
for i in range(m): for j in range(n): new_mat = flip(mat, i, j) new_mat_key = get_key(new_mat) if new_mat_key in visited: continue
q.append(new_mat) visited.add(new_mat_key)
step += 1
return -1