Leetcode 1374 Solution

This article provides solution to leetcode question 1374 (leftmost-column-with-at-least-a-one)
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https://leetcode.com/problems/leftmost-column-with-at-least-a-one

Solution

# """
# This is BinaryMatrix's API interface.
# You should not implement it, or speculate about its implementation
# """
#class BinaryMatrix(object):
#    def get(self, row: int, col: int) -> int:
#    def dimensions(self) -> list[]:



class Solution:
    def leftMostColumnWithOne(self, binaryMatrix: 'BinaryMatrix') -> int:
        m, n = binaryMatrix.dimensions()



        ans = n
        for i in range(m):
            l = 0
            r = min(ans, n - 1)



            while l < r:
                m = (l + r) // 2



                if binaryMatrix.get(i, m):
                    r = m
                else:
                    l = m + 1



            if binaryMatrix.get(i, l):
                ans = min(ans, l)



        return ans if ans != n else -1