Leetcode 1227 Solution
This article provides solution to leetcode question 1227 (number-of-equivalent-domino-pairs)
Access this page by simply typing in "lcs 1227" in your browser address bar if you have bunnylol configured.
Leetcode Question Link
https://leetcode.com/problems/number-of-equivalent-domino-pairs
Solution
class Solution:
def numEquivDominoPairs(self, dominoes: List[List[int]]) -> int:
a = {}
res = 0
for domino in dominoes:
min_val = min(domino[0], domino[1])
max_val = max(domino[0], domino[1])
k = (min_val, max_val)
if k not in a:
a[k] = 0
old_cnt = a[k]
res += old_cnt
a[k] += 1
return res